Binomial TheoremHard
Question
In the expansion of
, the 11th term is a:
Options
A.positive integer
B.positive irrational number
C.negative integer
D.negative irrational number
Solution
T11 = 15C10 (3)5 
= 15C10(3)5
= a positive irrational number
= 15C10(3)5
Create a free account to view solution
View Solution FreeMore Binomial Theorem Questions
Given positive integers r > 1, n > 2and the coefficient of (3r) th and (r + 2) th term in the binomial expansion of (1 +...is equal to -...If the coefficients of the three successive terms in the binomial expansion of (1 + x)n are in the ratio 1 : 7 : 42, the...In the expansion of , n ∈ N, if the sum of the coefficients of x5 and x10 is 0, then n is :...If the coefficients of x7 & x8 in the expansion of are equal, then the value of n is -...