Binomial TheoremHard
Question
In the expansion of
, the 11th term is a:
Options
A.positive integer
B.positive irrational number
C.negative integer
D.negative irrational number
Solution
T11 = 15C10 (3)5 
= 15C10(3)5
= a positive irrational number
= 15C10(3)5
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