Binomial TheoremHard
Question
In the expansion of (71/3 + 111/9)6561, the number of terms free from radicals is:
Options
A.730
B.729
C.725
D.750
Solution
Tr+1 = 6561Cr 
(111/9)r
Here r should be multiple of 9
r = 0, 9,18...............6561
Number of terms = 730
(111/9)rHere r should be multiple of 9
r = 0, 9,18...............6561
Number of terms = 730
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