ElectroMagnetic InductionHard
Question
Two coils are at fixed locations. When coil 1 has no current and the current in coil 2 increases at the rate 15.0 A/s the e.m.f. is coil 1 in 25.0 mV, when coil 2 has no current and coil 1 has a current of 3.6 A, flux linkage in coil 2 is
Options
A.16 mWb
B.10 mWb
C.4.00 mWb
D.6.00 mWb
Solution
EMF f = 
25 × 10-3 = M × 15
or M =
× 10-3 H
φ = MI = × 10-3 × 3.6 = 6.00 mWb.
25 × 10-3 = M × 15or M =
× 10-3 H φ = MI =
× 10-3 × 3.6 = 6.00 mWb.Create a free account to view solution
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