ElectroMagnetic InductionHard
Question
A rod of length 10 cm made up of conducting and non-conducting material (shaded part is non-conducting). The rod is rotated with constant angular velocity 10 rad/sec about point O, in constant magnetic field of 2 Tesla as shown in the figure. The induced emf between the point A and B of rod will be
Options
A.0.029 v
B.0.1 v
C.0.051 v
D.0.064 v
Solution
ε = 
=
=
× (100 − 49) × 10-4
= 10-3 × 51 = 0.051 volt.
=
=
× (100 − 49) × 10-4= 10-3 × 51 = 0.051 volt.
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