Continuity and DifferentiabilityHard
Question
If y2 = P(x) is a polynomial of degree 3, then 2
is equal to
Options
A.P″′(x) + P′(x)
B.P″(x). P″′(x)
C.P(x) . P″′(x)
D.a constant
Solution
y2 = P(x)
⇒ 2y
= P′(x)
⇒
⇒
⇒ 2y3
= y2 P″(x) - P′(x) . y 
⇒ 2y3 = P(x) P″(x) -
∵ y2 = P(x) & y 
⇒
= P′(x) . P″(x) + P(x) . P″′(x) - 2
∴
= P(x) . P″′(x)
⇒ 2y
⇒
⇒
⇒ 2y3
⇒ 2y3 = P(x) P″(x) -
⇒
= P′(x) . P″(x) + P(x) . P″′(x) - 2
∴
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