DifferentiationHard
Question
If x 
= 0, then 
is equal to
= 0, then is equal toOptions
A.
B.
C.
D.
Solution
x 
= 0
x2 (1 + y) = y2 (1 + x)
x2 - y2 + x2y - y2x = 0
(x + y) (x - y) + xy (x - y) = 0
(x - y) (x + y + xy) = 0
∵ x ≠ y ⇒ y = -
⇒
= 0x2 (1 + y) = y2 (1 + x)
x2 - y2 + x2y - y2x = 0
(x + y) (x - y) + xy (x - y) = 0
(x - y) (x + y + xy) = 0
∵ x ≠ y ⇒ y = -
⇒
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