DifferentiationHard
Question
If u = ax + b, then 
(f(ax + b)) is equal to
(f(ax + b)) is equal toOptions
A.
(f(u))
(f(u)) B.a (f(u))
(f(u)) C.an (f(u))
(f(u)) D.a-n (f(u))
(f(u)) Solution
u = ax + b
Let y = f(ax + b)
= a f′(ax + b)
= a2 f″(ax + b)
= a3 f″′(ax + b)
:
= an fn (ax + b)
⇒
f(ax + b) = an fn (u) = an 
f(u)
Let y = f(ax + b)
= a f′(ax + b) = a2 f″(ax + b)= a3 f″′(ax + b):
= an fn (ax + b)⇒
f(ax + b) = an fn (u) = an f(u)Create a free account to view solution
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