Continuity and DifferentiabilityHard

Question

If x^y . y^x = 1, then equals to

Options

A.

B.

C.

D.

Solution

x^y . y^x = 1 ⇒ y lnx + x lny = 0
Diff. w.r.t. x, we get

. lnx + + lny +

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