Continuity and DifferentiabilityHard
Question
Let f(x) =
. Then
is equal to
Options
A.2
B.-2
C.-1
D.0
Solution
f′(x) = 
= x2 sin x + 2x tan x - 2 sin x + x2 sec2 x + 2 sin x - 2x cos x
⇒
= 0 + 0 - 2 + 0 + 0 + 2 - 2 = - 2
= x2 sin x + 2x tan x - 2 sin x + x2 sec2 x + 2 sin x - 2x cos x
⇒
= 0 + 0 - 2 + 0 + 0 + 2 - 2 = - 2
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