Current Electricity and Electrical InstrumentMedium

Question

In the network shown, points A, B and C are potentials of 70 V, zero and 10 V respectively.

Options

A.Point D is at a potential of 40 V
B.The currents in the sections AD, DB, DC are in the ratio  3: 2: 1
C.The currents in the sections AD, DB, DC are in the ratio 1: 2: 3
D.The network draws a total power of 200 W.

Solution


Let potential of point D is x. by KCL at point D.
I1 + I2 + I3 = 0
+ + = 0
⇒    6x − 420 + 3x + 2x − 20 = 0
⇒    11x = 440
⇒     x = 40 volt
∴    I1 = = −  3A,                      I2 = = 2A
        i3 = = 1A
        P = i2R
        P = 32 × 10 + 22 × 20 + 12 × 30
        P = 200 W

Create a free account to view solution

View Solution Free
Topic: Current Electricity and Electrical Instrument·Practice all Current Electricity and Electrical Instrument questions

More Current Electricity and Electrical Instrument Questions

The value of total resistance between x and y in ohm is :-...A galvanometer has a resistance of 20Ω and reads full - scale when 0.2 V is applied across it. To convert it into a...In a balanced wheat stone bridge, current in the galvanometer is zero. It remains zero when...In the adjacent circuit, AB is a potentiometer wires of length 40 cm no resistance per unit length 50Ω /m. As shown...A steady current flows in a metalic conductor of non-uniform cross section. The quantity/ quantities constant along the ...