Current Electricity and Electrical InstrumentHard
Question
In the network shown, points A, B and C are potentials of 70 V, zero and 10 V respectively.
Options
A.Point D is at a potential of 40 V
B.The currents in the sections AD, DB, DC are in the ratio 3: 2: 1
C.The currents in the sections AD, DB, DC are in the ratio 1: 2: 3
D.The network draws a total power of 200 W.
Solution
Let potential of point D is x. by KCL at point D.
I1 + I2 + I3 = 0
+ 
+ 
= 0⇒ 6x − 420 + 3x + 2x − 20 = 0
⇒ 11x = 440
⇒ x = 40 volt
∴ I1 =
= − 3A, I2 = 
= 2Ai3 =
= 1AP = i2R
P = 32 × 10 + 22 × 20 + 12 × 30
P = 200 W
Create a free account to view solution
View Solution FreeTopic: Current Electricity and Electrical Instrument·Practice all Current Electricity and Electrical Instrument questions
More Current Electricity and Electrical Instrument Questions
When a voltmeter is conected across the terminals of a cell, it measure 9 Volt. If a resistance of 1.5 Ω is connect...An energy source will supply a constant current into the load of its internal resistance is...A rectangular loop has a sliding connector PQ of length l and resistance RΩ and it is moving with a speed v as show...In the circuit shown in figure....There are 8.4 × 1022 free electrons per cm3 in copper. The current in the wire is 0.21 A (e = 1.6 × 10-19 C). ...