JEE Main | 2017Current Electricity and Electrical InstrumentMedium
Question
When a current of 5 mA is passed through a galvanometer having a coil of resistance 15 Ω, it shows full scale deflection. The value of the resistance to be put in series with the galvanometer to convert it into a voltmeter of range 0-10 V is
Options
A.
1.985 × 103Ω
B.
2.045 × 103Ω
C.
2.535 × 103Ω
D.
4.005 × 103Ω
Solution
ig = 5 × 10–3 A
G = 15 Ω
Let series resistance be R.
V = ig(R + G)
10 = 5 × 10–3 (R + 15)
R = 2000 – 15 = 1985 = 1.985 × 103 Ω
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