Trigonometric EquationHard
Question
In a DPQR, if 3 sinP + 4 cosQ = 6 and4 sinQ + 3 cos P = 1, then the angle R is equal to:
Options
A.
B.
C.
D.
Solution
3sinP + 4cosQ = 6 ..... (1)
4sinQ + 3cosP = 1 ..... (2)
Squaring (1) and (2). Then adding
9 + 16 + 24sin(P + Q) = 37
⇒ 24sin (P + Q) = 12
⇒ sin(P + Q)
⇒ sinR
∴
But
does′t satisfy the given equation so 
4sinQ + 3cosP = 1 ..... (2)
Squaring (1) and (2). Then adding
9 + 16 + 24sin(P + Q) = 37
⇒ 24sin (P + Q) = 12
⇒ sin(P + Q)
⇒ sinR ∴
But
does′t satisfy the given equation so Create a free account to view solution
View Solution FreeMore Trigonometric Equation Questions
dx is equal to...The number of solutions of the pair of equations 2 sin2θ - cos2θ = 0 2 cos2θ - 3 sinθ = 0 in the int...loge (1 + cos x) dx is equal to...If f : R → S defined by f(x) = sin x − √3 cos x + 1, is onto, then the interval of S is...Consider f(x) = cos2x(2cos2x + 3sinxcosx) + ax, where a ∈ R, Value(s) of ′a′ for which f(x) is strictl...