Trigonometric EquationHard
Question
In a DPQR, if 3 sinP + 4 cosQ = 6 and4 sinQ + 3 cos P = 1, then the angle R is equal to:
Options
A.
B.
C.
D.
Solution
3sinP + 4cosQ = 6 ..... (1)
4sinQ + 3cosP = 1 ..... (2)
Squaring (1) and (2). Then adding
9 + 16 + 24sin(P + Q) = 37
⇒ 24sin (P + Q) = 12
⇒ sin(P + Q)
⇒ sinR
∴
But
does′t satisfy the given equation so 
4sinQ + 3cosP = 1 ..... (2)
Squaring (1) and (2). Then adding
9 + 16 + 24sin(P + Q) = 37
⇒ 24sin (P + Q) = 12
⇒ sin(P + Q)
⇒ sinR ∴
But
does′t satisfy the given equation so Create a free account to view solution
View Solution FreeMore Trigonometric Equation Questions
General solution of sin3x + cos3x + sin2x = 1...If 0 ≤ x ≤ 2π, 0 ≤ y ≤ 2π and sin x + sin y = 2 then the value of x + y is-...If 2 cot2 θ = cosec2 θ, then the general value of θ is -...A point is randomly selected inside a square of side length 3m. If probability that selected point lies at a distance gr...If = 0. So find the general value of θ...