Trigonometric EquationHard
Question
In a DPQR, if 3 sinP + 4 cosQ = 6 and4 sinQ + 3 cos P = 1, then the angle R is equal to:
Options
A.
B.
C.
D.
Solution
3sinP + 4cosQ = 6 ..... (1)
4sinQ + 3cosP = 1 ..... (2)
Squaring (1) and (2). Then adding
9 + 16 + 24sin(P + Q) = 37
⇒ 24sin (P + Q) = 12
⇒ sin(P + Q)
⇒ sinR
∴
But
does′t satisfy the given equation so 
4sinQ + 3cosP = 1 ..... (2)
Squaring (1) and (2). Then adding
9 + 16 + 24sin(P + Q) = 37
⇒ 24sin (P + Q) = 12
⇒ sin(P + Q)
⇒ sinR ∴
But
does′t satisfy the given equation so Create a free account to view solution
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