Trigonometric EquationHard
Question
The number of solutions of the pair of equations
2 sin2θ - cos2θ = 0
2 cos2θ - 3 sinθ = 0
in the interval [0, 2π] is
2 sin2θ - cos2θ = 0
2 cos2θ - 3 sinθ = 0
in the interval [0, 2π] is
Options
A.zero
B.one
C.two
D.four
Solution
2sin2θ - cos2θ = 0 ⇒ sin2θ = 
also 2cos2θ = 3sinθ ⇒ sinθ =
⇒ two solutions in [0, 2π].
also 2cos2θ = 3sinθ ⇒ sinθ =
⇒ two solutions in [0, 2π].
Create a free account to view solution
View Solution FreeMore Trigonometric Equation Questions
The solution of equation 13 − 4 cos2x = 12 sin x is -...(t sin(2010t) + 2009t + 1006) dx is equal to -...(sin-1|x| + cos-1x) can be equal to -...If cot(3α - 7β) tan (5β - α) = 1, α∈(0, π), β∈ and L = 2√2 sin , th...If r > 0, −π ≤ θ ≤ π and r, θ satisfy r sinθ = 3 and r = 4 (1 + sin θ...