Trigonometric EquationHard
Question
The number of solutions of the pair of equations
2 sin2θ - cos2θ = 0
2 cos2θ - 3 sinθ = 0
in the interval [0, 2π] is
2 sin2θ - cos2θ = 0
2 cos2θ - 3 sinθ = 0
in the interval [0, 2π] is
Options
A.zero
B.one
C.two
D.four
Solution
2sin2θ - cos2θ = 0 ⇒ sin2θ = 
also 2cos2θ = 3sinθ ⇒ sinθ =
⇒ two solutions in [0, 2π].
also 2cos2θ = 3sinθ ⇒ sinθ =
⇒ two solutions in [0, 2π].
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