Current Electricity and Electrical InstrumentHard
Question
The potential difference between the terminals of a battery of emf 10 V and internal resistance 1Ω drops to 9.8 V when connected across an external resistance. The resistance of the external resistor is :
Options
A.49 Ω
B.25 Ω
C.31 Ω
D.43 Ω
Solution
V = E − Ir ⇒ 9.8 = 10 − I .1
I = 0.2 amp R =
= 49 Ω
I = 0.2 amp R =
= 49 ΩCreate a free account to view solution
View Solution FreeTopic: Current Electricity and Electrical Instrument·Practice all Current Electricity and Electrical Instrument questions
More Current Electricity and Electrical Instrument Questions
The resistance of a wire is 'R' ohm. If it is melted and stretched to 'n' times its original length, its...Ratio of equivalent resistance between A and B in two cases will be :-(a) (b)...A voltmeter of 998 ohm resistance is connected to a cell of emf 2 volt, having internal resistance of 2 ohms, The error ...In the presence of an applied electric field () in a metallic conductor....Find the resistance of a wire frame shaped as a cube (figure) when measured between points 1-7...