Current Electricity and Electrical InstrumentHard
Question
The potential difference between the terminals of a battery of emf 10 V and internal resistance 1Ω drops to 9.8 V when connected across an external resistance. The resistance of the external resistor is :
Options
A.49 Ω
B.25 Ω
C.31 Ω
D.43 Ω
Solution
V = E − Ir ⇒ 9.8 = 10 − I .1
I = 0.2 amp R =
= 49 Ω
I = 0.2 amp R =
= 49 ΩCreate a free account to view solution
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