Current Electricity and Electrical InstrumentHard
Question
In the previous question potential at point 0 is
Options
A.15 V
B.20 V
C.25 V
D.8 V
Solution

Apply KCL for circuit
6V − 60 + 3V − 18 + 2V − 10 = 0 ⇒ 11V = 88 ⇒ V = 8 V Ans
current in resistance R1 =
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