Current Electricity and Electrical InstrumentHard

Question

In the previous question potential at point 0 is

Options

A.15 V
B.20 V
C.25 V
D.8 V

Solution


Apply KCL for circuit  = 0
6V − 60 + 3V − 18 + 2V − 10 = 0    ⇒    11V = 88    ⇒    V = 8 V        Ans
current in resistance R1 = = 0.2 amp

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