If y = ln , then x3 is equals to

y = x(lnx - ln (a + bx)) ... (1)⇒ = lnx - ln (a + bx) + ... (2)⇒ ⇒ x3 ... (3)By (1) and (2), x - y = ⇒ x3

Continuity and DifferentiabilityHard

Question

If y = ln , then x³ is equals to

D.None of these

y = x(lnx - ln (a + bx))               ... (1)
⇒ = lnx - ln (a + bx) +     ... (2)
⇒
⇒ x³         ... (3)
By (1) and (2),
x - y =
⇒ x³

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