Continuity and DifferentiabilityHard
Question
If x = cosecθ - sinθ ; y = cosecnθ - sinnθ, then (x2 + 4) 
- n2y2 equals to
- n2y2 equals toOptions
A.n2
B.2n2
C.3n2
D.4n2
Solution
∴ x = cosec θ - sinθ
⇒ x2 + 4 = (cosecθ + sinθ)2
and y2 + 4 = (cosecnθ + sinnθ)2
Now
Squaring both sides, we get
or (x2 + 4)
= n2 (y2 + 4)
⇒ x2 + 4 = (cosecθ + sinθ)2
and y2 + 4 = (cosecnθ + sinnθ)2
Now
Squaring both sides, we get
or (x2 + 4)
= n2 (y2 + 4) Create a free account to view solution
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