LimitsHard

Question

If exists and finite, then possible values of ′n′ and ′k′ is :

Options

A.k = 3 , n = 2
B.k = 3 , n = - 2
C.k = 5 , n = 2
D.k = - 5 , n = 2

Solution




limit exists, if coff. of x2 is zero.
⇒  n2 + - k = 0    ⇒    4k = 5n2
so the possible value match that is  n = 2
                          k = 5

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