Current Electricity and Electrical InstrumentHard
Question
The current density in a wire is 10 A/cm2 and the electric field in the wire is 5 V/cm. If ρ = resistivity of material, σ = conductivity of the material then (in S.I. units) :
Options
A.ρ = 5 × 10-3
B.ρ = 200
C.σ = 5 × 10-3
D.σ = 200
Solution
IR = V = El ⇒ I 
⇒ 
= 
= 5 × 10-3Ω-m
σ =
= 200 mho/m.
⇒ = = 5 × 10-3Ω-mσ =
= 200 mho/m.Create a free account to view solution
View Solution FreeTopic: Current Electricity and Electrical Instrument·Practice all Current Electricity and Electrical Instrument questions
More Current Electricity and Electrical Instrument Questions
A potentiometer is an accurate and versatile device to make electrical measurements of E.M.F. because the method involve...Figure shows the circuit that contains three resistances ( $9\Omega$ each) and two inductors ( 4 mH each). The reading o...In a meter bridge set up, which of the following should be the properties of the one long wire ?...The total resistance between x and y in ohm is : -...A potential gradient is created in the wire by a standared cell for the comparision of emf′s of two cells in a pot...