Current Electricity and Electrical InstrumentHard
Question
The current density in a wire is 10 A/cm2 and the electric field in the wire is 5 V/cm. If ρ = resistivity of material, σ = conductivity of the material then (in S.I. units) :
Options
A.ρ = 5 × 10-3
B.ρ = 200
C.σ = 5 × 10-3
D.σ = 200
Solution
IR = V = El ⇒ I 
⇒ 
= 
= 5 × 10-3Ω-m
σ =
= 200 mho/m.
⇒ = = 5 × 10-3Ω-mσ =
= 200 mho/m.Create a free account to view solution
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