Current Electricity and Electrical InstrumentHard

Question

The current density in a wire is 10 A/cm2 and the electric field in the wire is 5 V/cm. If ρ = resistivity of material, σ = conductivity of the material then (in S.I. units) :

Options

A.ρ = 5 × 10-3
B.ρ = 200
C.σ = 5 × 10-3
D.σ = 200

Solution

IR = V = El     ⇒ I   ⇒ = = 5 × 10-3Ω-m
σ =  = 200 mho/m.

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