Circular MotionHard
Question
A particle is projected horizontally from the top of a tower with a velocity v0. If v be its velocity at any instant, then the radius of curvature of the path of the particle at that instant is directly proportional to:
Options
A.v3
B.v2
C.v
D.1/v
Solution
As we know :
aC =
(centripetal acceleration) From figure ; g sin θ =
⇒ g.
= 
(since sin θi = 
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