NEET | 2016Circular MotionHard

Question

A uniform circular disc of radius 50 cm at rest is free to tum about an axis which is perpendicular to its planeand passes through its centre. It is subjected to a torque which produces a constant angular acceleration of 2.0 rad s-2. Its net acceleration in ms-2 at the end of 2.0 s is approximately:

Options

A.

8.0

B.

7.0

C.

6.0

D.

3.0

Solution

At the end of 2 sec, w = w0 + αt
w = 0 + 2(2) = 4 rad/sec
Particle acceleration towards the center is = ac = rw2
ar = 12(4)2 = 8 m/s

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