NEET | 2016Rotational MotionEasy
Question
A uniform circular disc of radius 50 cm at rest is free to tum about an axis which is perpendicular to its planeand passes through its centre. It is subjected to a torque which produces a constant angular acceleration of 2.0 rad s-2. Its net acceleration in ms-2 at the end of 2.0 s is approximately:
Options
A.
8.0
B.
7.0
C.
6.0
D.
3.0
Solution
At the end of 2 sec, w = w0 + t
w = 0 + 2(2) = 4 rad/sec
Particle acceleration towards the center is = ac = rw2
ar = (4)2 = 8 m/s
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