Circular MotionHard
Question
A car is moving with constant speed on a road as shown in figure. The normal reaction by the road on the car is NA , NB and NC when it is at the points A, B and C respectively.
Options
A.NA = NB
B.NA > NB
C.NA < NB
D.NC > NA
Solution
For normal reaction at points A and B.
mg − N =
N = mg −
⇒ NA > NB and normal reaction at C is NC = mg, so NC > NA > NB Ans.
mg − N =
N = mg −
⇒ NA > NB and normal reaction at C is NC = mg, so NC > NA > NB Ans.
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