Circular MotionMedium
Question
A car is moving with constant speed on a road as shown in figure. The normal reaction by the road on the car is NA , NB and NC when it is at the points A, B and C respectively.
Options
A.NA = NB
B.NA > NB
C.NA < NB
D.NC > NA
Solution
For normal reaction at points A and B.
mg − N =
N = mg −
⇒ NA > NB and normal reaction at C is NC = mg, so NC > NA > NB Ans.
mg − N =
N = mg −
⇒ NA > NB and normal reaction at C is NC = mg, so NC > NA > NB Ans.
Create a free account to view solution
View Solution FreeMore Circular Motion Questions
In the above question, . is non-negative at the lowest point for:...A train A runs from east to west and another train B of the same mass runs from west to east at the same speed along the...A spherically symmetric gravitational system of particles has a mass density ρ = where ρ0 is a constant. A tes...The second′s hand of a watch has length 6 cm. Speed of end point and magnitude of difference of velocities at two ...A bead $P$ sliding on a frictionless semi-circular string $(ACB)$ and it is at point $S$ at $t = 0$ and at this instant ...