Circular MotionMedium
Question
A particle is kept fixed on a uniformly rotating turn-table As seen from the ground , the particle goes in a circle, its speed is 10 cm/s and acceleration is 10 cm/s2.The particle is now shifted to a new position to make the radius half of the original value.The new values of the speed and acceleration will be
Options
A.20 cm/s, 20 cm/s2
B.10 cm/s, 80 cm/s2
C.40 cm/s, 10 cm/s2
D.40 cm/s,40 cm/s2
Solution
Uniformly rotating turn table means angular velocity is constant. New radius is half of the original value.
r′ = 2r and ω = constant
v′ = ωr′ = 2ωr = 2v = 20 cm/s Ans.
a′ = ω2 r′= 2ω2r = 2a = 20 cm/s2 Ans.
r′ = 2r and ω = constant
v′ = ωr′ = 2ωr = 2v = 20 cm/s Ans.
a′ = ω2 r′= 2ω2r = 2a = 20 cm/s2 Ans.
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