LimitsHard

Question

If (cos x + a sin bx)1/x = e2, then the possible values of  ′a′  &  ′b′ are :

Options

A.a = 1, b = 2
B.a = 2 , b = 1
C.a = 3, b = 2/3
D.a = 2/3, b = 3

Solution

(cos x + a sin bx)1/x = e2      = e2    (1∞ form)


⇒ (- sin x + ab cos bx) = 2
⇒  ab = 2
∴  a = 1, b = 2;     a = 2, b = 1;    a = 3, b = ;    a =, b = 3

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