JEE Advanced | 2013LimitsHard

Question

For a ∈ R (the set of all real numbers), a ≠ 1.

Then a =

Options

A.5
B.7
C.
D.

Solution



⇒ 2a2 + 3a - 119 = 0 ⇒ a = 7

Create a free account to view solution

View Solution Free
Topic: Limits·Practice all Limits questions

More Limits Questions

The value of (cos ax) cosec2tx is -...equals-...equals-...Which of the following limits does not exist-...Let f(x) = , x ≠ . The value of fso that the function is continuous at x = π/2 is:...