Indefinite IntegrationHard
Question
The value of 
dx equals :
dx equals :Options
A.
(ln |x| - 2) + C
(ln |x| - 2) + C B. (ln |x| + 2) + C
(ln |x| + 2) + CC.
(ln |x| - 2) + C
(ln |x| - 2) + CD.2 
(3 ln |x| - 2) + C
(3 ln |x| - 2) + CSolution
I = 
dx Put 1 + ln| x | = t2, then 
dx = 2t dt
⇒ I =
. 2t dt = 2 
+ C = 
(ln |x| – 2) + C
dx Put 1 + ln| x | = t2, then dx = 2t dt ⇒ I =
. 2t dt = 2 + C = (ln |x| – 2) + CCreate a free account to view solution
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