Indefinite IntegrationHard

Question

If dx = A ln |x| + + C, where C is the constant of integration, then:

Options

A.A = 1; B = - 1
B.A = - 1; B = 1
C.A = 1; B = 1
D.A = - 1; B = - 1

Solution

dx = A ln |x| + + C
differetiate both side w.r.t. x.

So    x4 + 1 = A(1 + x2)2 - B(2x2)
A = 1 and B = 1
Alternate :


= ln |x| + + C

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