Indefinite IntegrationHard
Question
The value of ∫ (sin x. cos x. cos 2x. cos 4x. cos 8x. cos 16 x) dx is equal to
Options
A.
B.
C.
D.
Solution
∫sin x cos x cos 2x cos 4x. cos 8x. cos16x dx
=
∫2 sin x cos x. cos2x cos4x cos8x cos16x dx
=
∫sin 32 x dx = - 
× cos 32x + C = - 
+ C
=
∫2 sin x cos x. cos2x cos4x cos8x cos16x dx=
∫sin 32 x dx = - × cos 32x + C = - + CCreate a free account to view solution
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