Indefinite IntegrationHard
Question
If 
= a ln (1 + x2) + btan-1x + 
ln | x + 2 | + C then -
= a ln (1 + x2) + btan-1x + ln | x + 2 | + C then -Options
A.a = - 
, b = - 
, b = - B.a = , b = -
, b = - C.a = - 1 , b =
, b = D.a = , b =
, b = Solution
Let 
On solving it we get A = -
, B = 
, C = 
∴
dx
=
ln (x2 + 1) + 
tan-1 x +
ln | x + 2 | + K
On solving it we get A = -
, B = , C = ∴
dx=
ln (x2 + 1) + tan-1 x +ln | x + 2 | + KCreate a free account to view solution
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