CapacitanceHard
Question
Two capacitors of 2 μF & 3 μF are charged to 150 volt & 120 volt respectively. The plates of a capacitor are connected as shown in the fig. A discharged capacitor of capacity 1.5 μF falls to the free ends of the wire and connected through the free ends of the wire, Then :
Options
A.Charge on the 1.5 μF capacitor will become 180 μC at steady state.
B.Charge on the 2 μF capacitor will become 120 μC at steady state.
C.Positive charge flows through point A from left to right.
D.Positive charge flows through point A from right to left.
Solution
VA +
= VAby solve this equation we get ⇒ q = 180μC
Charge on 1.5μF capacitor is = 150πC
Charge on 2μF capacitor is = 300 − 180 = 120μC
Therefore charge flows through A from left to right .
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