CapacitanceMedium
Question
Two capacitors of 2 μF & 3 μF are charged to 150 volt & 120 volt respectively. The plates of a capacitor are connected as shown in the fig. A discharged capacitor of capacity 1.5 μF falls to the free ends of the wire and connected through the free ends of the wire, Then :
Options
A.Charge on the 1.5 μF capacitor will become 180 μC at steady state.
B.Charge on the 2 μF capacitor will become 120 μC at steady state.
C.Positive charge flows through point A from left to right.
D.Positive charge flows through point A from right to left.
Solution
VA +
= VAby solve this equation we get ⇒ q = 180μC
Charge on 1.5μF capacitor is = 150πC
Charge on 2μF capacitor is = 300 − 180 = 120μC
Therefore charge flows through A from left to right .
Create a free account to view solution
View Solution FreeMore Capacitance Questions
The electric field at a distance from the centre of a charged conducting spherical shell of radius R is E. The electric ...Two thin dielectric slabs of dielectric constants K2 and K2 (K1 2) are inserted between plates of a parallel plate capac...The plates of a parallel plate capacitor with no dielectric are connected to a voltage source. Now a dielectric of diele...Three capacitors of value 6, 3 and 9 μF are joined according to the circuit and then the combination is connected w...A parallel plate air capacitor is connected to a battery. The plates are pulled apart at uniform speed $v$. If x is the ...