CapacitanceHard
Question
In series L-C circuit inductance is 2mH and capacitance is 400μF and supply voltage is 100V. If frequency of source is 103 rad/sec then what will be potential difference across inductor :-
Options
A.400 V
B.zero
C.200 V
D.200 √2
Solution
XL = ωL = 103 × 2 × 10-3 = 2Ω
XC =
= 2.5 Ω
Z = XL - XC = 0.5Ω
I =
= 200A
VL = IXL = 200 × 2 = 400V
XC =
= 2.5 ΩZ = XL - XC = 0.5Ω
I =
= 200AVL = IXL = 200 × 2 = 400V
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