CapacitanceHard
Question
In the circuit shown in figure, each capacitor has a capacitance C. The emf of the cell is E. If the switch S is closed.
Options
A.some positive charge will flow out of the positive terminal of the cell
B.some positive charge will enter the positive terminal of the cell
C.the amount of charge flowing through the cell will be CE
D.the amount of charge flowing through the cell will be (4/3) CE
Solution
equivalent capacitance before switch closed is Ceq = 
Total charge flow through the cell is q =
equivalent capacitance after switch S closed is Ceq = 2C
Total charge flow through the cell is q = 2CE
Therefore some positive charge flow through the cell after closing the switch is = qf − qi = 2CE −
Total charge flow through the cell is q =
equivalent capacitance after switch S closed is Ceq = 2C
Total charge flow through the cell is q = 2CE
Therefore some positive charge flow through the cell after closing the switch is = qf − qi = 2CE −
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