CapacitanceHard
Question
Rows of capacitors containing 1,2,4,8,..........∞ capacitors, each of capacitance 2F, are connected in parallel as shown in figure. The potential difference across AB = 10 volt, then :


Options
A.Total capacitance across AB is 4F
B.Charge of each capacitor will be same
C.Charge on the capacitor in the first row is more than on any other capacitor
D.Energy of all the capacitors is 50 J
Solution
C = 2μF
Ceq = C +
+.................
Ceq = C
= 4μF
Charge on first row capacitor is q1 = 2 × 10μC = 20μC
Charge on second row capacitor is q2 = 1 × 10μC = 10μC
Charge on third row capacitor is q3 =
× 10μC = 5μC
Therefore charge on the capacitor in the first row is more than on any other capacitor.
Energy stored in all capacitor is =
Ceq V2 =
Ceq V2 = × 4 × 10-6 × (10)2 = 0.2 μJ Ans
C = 2μF
Ceq = C +
Ceq = C
Charge on first row capacitor is q1 = 2 × 10μC = 20μC
Charge on second row capacitor is q2 = 1 × 10μC = 10μC
Charge on third row capacitor is q3 =
Therefore charge on the capacitor in the first row is more than on any other capacitor.
Energy stored in all capacitor is =
C = 2μF
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