CapacitanceHard

Question

On a parallel plate capacitor following operations can be performed.
P - connect the capacitor to a battery of emf V
Q - disconnect the battery
R - reconnect the battery with polarity reversed
S - insert a dielectric slab in the capacitor

Options

A.In PQR (perform P, then Q, then R), the stored electric energy remains unchanged and no thermal energy is developed   
B.The charge appearing on the capacitor is greater after the action PSQ then after the action PQS
C.The electric energy stored in the capacitor is greater after the action SPQ then after the action PQS
D.The electric field in the capacitor after the action PS is the same as that after SP

Solution

In PQS process charge on capacitor is Q = CV
In PSQ process charge on capacitor is Q′ = KCV
Electric energy stored in PQS is = CV2
Electric energy stored in PSQ is = KCV2
UPSQ > UPQS
Electric field in PS is E =
Electric field in SP is E =
EPS  = ESP

Create a free account to view solution

View Solution Free
Topic: Capacitance·Practice all Capacitance questions

More Capacitance Questions

Three parallel plate capacitors each with area A and separation d are filled with two dielectric ( $k_{1}$ and $k_{2}$ )...Two electric bulbs rated P1 watt V volt and P2 watt V volt are applied to it. The total power will be:-...In the given circuit, a charge of + 80μC is given to the upper plate of the 4μF capacitor. Then in the steady ...In an isolated parallel plate capacitor of capacitance C the four surfaces have charges Q1,Q2,Q3 and Q4 as shown in the ...In the adjoining circuit, the capacity between the points A and B will be -...