CapacitanceHard
Question
In an isolated parallel plate capacitor of capacitance C the four surfaces have charges Q1,Q2,Q3 and Q4 as shown in the figure. The potential difference between the plates is :


Options
A.
B.
C.
D.
[(Q1 + Q2) − (Q3 − Q4)]
Solution


Charge on outer surfaces are equal so Q1 = Q3 + Q2 + Q4 and Q1 + Q2 + Q3 = Q4
V =
Adding (i) and (ii)
Q1 = Q4 and Q2 = − Q3
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