CapacitanceHard
Question
In the following figure, the charge on each condenser in the steady state will be-
Options
A.3μC
B.6μC
C.9μC
D.12μC
Solution
Charge on each capacitor will be same. In steady state current through capacitor will be zero
current in steady state = i 10/5 = 2 amp
potential across AB = iR = 2 × 4 = 8 V.
on each plate Q = C V = 3 × 4 = 12 μC
current in steady state = i 10/5 = 2 amp
potential across AB = iR = 2 × 4 = 8 V.
on each plate Q = C V = 3 × 4 = 12 μC
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