CapacitanceHard

Question

n resistances each of resistance R are joined with capacitors of capacity C (each) and a battery of emf E as shown in the figure. In steady state condition ratio of charge stored in the first and last  capacitor is :
                            

Options

A.n : 1
B.(n − 1) : (n + 1)
C.(n2 + 1) : (n2 − 1)
D.1 : 1

Solution


Qfirst = Qlast = CE
Ratio  = = 1.

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