FunctionHard
Question
If f(x) = cot-1x : R+ → 
and g(x) = 2x - x2 : R → R. Then the range of the function f(g(x)) wherever define is
and g(x) = 2x - x2 : R → R. Then the range of the function f(g(x)) wherever define is
Options
A.
B.
C.
D.
Solution
f(x) = cot-1x : R+ →
g(x) = 2x - x2 R → R
f(g(x)) = cot-1 (2x - x2), where x ∈ (0, 1]
hence f(g(x)) ∈
g(x) = 2x - x2 R → R
f(g(x)) = cot-1 (2x - x2), where x ∈ (0, 1]
hence f(g(x)) ∈
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