FunctionHard
Question
The domain of the functihon f (x) = 
is:
is:Options
A.(- 1, 0)
B.(- 1, 0) - 
C.(- 1, 0] - 
D.
Solution
f(x) = 
here - 1 ≤ 2x + 1 < 1 ⇒ - 2 ≤ 2x < 0 ⇒ - 1 ≤ x < 0
⇒ x ∈ [-1, 0)
But x ≠ - 1 as |x| - 1 ≠ 0
∴ x ∈ (-1, 0)
for x ∈ (-1, 0), (|x| - 1) is -ve
∴ tan 3x < 0
0 > 3x > -
x ∈ 
Domain :
∩ (-1, 0) ≡ 
here - 1 ≤ 2x + 1 < 1 ⇒ - 2 ≤ 2x < 0 ⇒ - 1 ≤ x < 0
⇒ x ∈ [-1, 0)
But x ≠ - 1 as |x| - 1 ≠ 0
∴ x ∈ (-1, 0)
for x ∈ (-1, 0), (|x| - 1) is -ve
∴ tan 3x < 0
0 > 3x > -
x ∈ Domain :
∩ (-1, 0) ≡ Create a free account to view solution
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