FunctionHard
Question
Let g (x) = 1 + x - [ x ] and f (x) =
. Then for all x, f (g (x)) is equal to (where [.] denotes greatest integer function)
Options
A.x
B.1
C.f(x)
D.g(x)
Solution
g(x) = 1 + {x}
f(x) = sgn (x)
∴ f(g(x)) = sgn (1 + {x}) = 1
f(x) = sgn (x)
∴ f(g(x)) = sgn (1 + {x}) = 1
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