FunctionHard
Question
Which one of the following pair of functions are identical ?
Options
A.e(lnx)/2 and √x
B.tan-1(tan x) and cot-1 (cot x)
C.cos2x + sin4x and sin2x + cos4x
D.
and sgn (x), where sgn(x) stands for signum function.
Solution
(A) f(x) = e1/2 ln x = √x, D : x > 0
g(x) = √x, D : x ≥ 0
(B) tan-1 (tan x) = x D : x ≠ ± (2n + 1)
cot-1 (cot x) = x D : x ≠ ±nπ
(C) f(x) = cos2x + sin4x
= cos2x + (1 - cos2x)2
= 1 - cos2x + cos4x
= sin2x + cos4x
g(x) = sin2x + cos4x
(D) f(x) =
, D : x ≠ 0
g(x) = sgn (x), D : x ∈ R
g(x) = √x, D : x ≥ 0
(B) tan-1 (tan x) = x D : x ≠ ± (2n + 1)
cot-1 (cot x) = x D : x ≠ ±nπ
(C) f(x) = cos2x + sin4x
= cos2x + (1 - cos2x)2
= 1 - cos2x + cos4x
= sin2x + cos4x
g(x) = sin2x + cos4x
(D) f(x) =
g(x) = sgn (x), D : x ∈ R
Create a free account to view solution
View Solution FreeMore Function Questions
Solution of (x − 1)2 (x + 4) < 0 is-...If y = f(x), then...If f (x) = sin (x)(where [ . ] denotes the greatest integer function) has π as its fundamental period, then -...Which of the following function is onto ?...Let f: (e, ∞) → R be defined by f(x) = ln (ln(ln x)), then...