FunctionHard
Question
Range of f(x) = ln (3x2 - 4x + 5) is
Options
A.
B.(B) [ln 10 , ∞)
C.
D.
Solution
f(x) = loge (3x2 - 4x + 5)
3x2 - 4x + 5 ≥
⇒ ln (3x2 - 4x + 5) ≥ in
[∵ ln is an increasing function]
∴ Range is
3x2 - 4x + 5 ≥
⇒ ln (3x2 - 4x + 5) ≥ in
[∵ ln is an increasing function]
∴ Range is
Create a free account to view solution
View Solution Free