CapacitanceHard
Question
A parallel plate condenser with plate separation d is charged with the help of a battery so that U0 energy is stored in the system. A plate of dielectric constant K and thickness d is placed between the plates of condenser while battery remains connected. The new energy of the system will be-
Options
A.KU0
B.K2U0
C.U0/K
D.U0/K2
Solution
U0 = 
CV2 (given) Now energy = U′ = 
C′V2
C′ = CK
U′ =
CV2K = UoK
CV2 (given) Now energy = U′ = C′V2C′ = CK
U′ =
CV2K = UoK Create a free account to view solution
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