CapacitanceHard
Question
In the above problem if the battery is disconnected before inserting the dielectric, then potential difference will be-
Options
A.1/2 V
B.2 V
C.4 V
D.32 V
Solution
Charge or battery = Q = CV = 4 C
Now charge remains same, as battery is disconnected new capacitance = C′ = KC = 8C
C′V′ = Q V′ =
V (A)
Now charge remains same, as battery is disconnected new capacitance = C′ = KC = 8C
C′V′ = Q V′ =
V (A) Create a free account to view solution
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