CapacitanceHard

Question

Let C be the capacitance of a capacitor discharging through a resistor R. Suppose t1 is the time taken for the energy stored in the capacitor to reduce to half its initial value and t2 is the time taken for the charge to reduce to one-fourth its initial value. Then the ratio t1/t2 will be :

Options

A.2
B.1
C.1/2
D.1/4

Solution

     
If   U = U0 ⇒ CVC2 = CV02
⇒  V = then t1 =
If Q = Q0 ⇒ CV′C = CV0
⇒ V′C = then t2 = 2T1/2
Therefore 

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