CapacitanceHard
Question
On placing a dielectric slab between the plates of an isolated charged condenser its-
Options
A.Capacitance → decreases
Charge → remains unchanged
Potential Difference → decreases
Energy stored → increases
Charge → remains unchanged
Potential Difference → decreases
Energy stored → increases
B.Capacitance → increases
Charge → remains unchanged
Potential Difference → increases
Energy stored → increases
Charge → remains unchanged
Potential Difference → increases
Energy stored → increases
C.Capacitance → increases
Charge → remains unchanged
Potential Difference → decreases
Energy stored → decreases
Charge → remains unchanged
Potential Difference → decreases
Energy stored → decreases
D.Capacitance → decreases
Charge → remains unchanged
Potential Difference → decreases
Energy stored → increases
Charge → remains unchanged
Potential Difference → decreases
Energy stored → increases
Solution
Q = constant
New capacitance = KC (increases)
V′ =
(decreases)
U′ =
(decreases)
E =
⇒ E′ = 
(decreases)
New capacitance = KC (increases)
V′ =
(decreases) U′ =
(decreases) E =
⇒ E′ = (decreases)Create a free account to view solution
View Solution FreeMore Capacitance Questions
In the given circuit, a charge of + 80μC is given to the upper plate of the 4μF capacitor. Then in the steady ...For the circuit shown in fig. Calculate the charge on 8μF capacitor...A parallel plate capacitor without any dielectric has capacitance C0. A dielectric slab is made up of two dielectric sla...Two parallel metal plates having charge + Q and - Q face other at a certain distance between them. If the plates are now...When air is replaced by a dielectric medium from the space between the plates of a charged parallel plate capacitor, the...