CapacitanceMedium
Question
On placing a dielectric slab between the plates of an isolated charged condenser its-
Options
A.Capacitance → decreases
Charge → remains unchanged
Potential Difference → decreases
Energy stored → increases
Charge → remains unchanged
Potential Difference → decreases
Energy stored → increases
B.Capacitance → increases
Charge → remains unchanged
Potential Difference → increases
Energy stored → increases
Charge → remains unchanged
Potential Difference → increases
Energy stored → increases
C.Capacitance → increases
Charge → remains unchanged
Potential Difference → decreases
Energy stored → decreases
Charge → remains unchanged
Potential Difference → decreases
Energy stored → decreases
D.Capacitance → decreases
Charge → remains unchanged
Potential Difference → decreases
Energy stored → increases
Charge → remains unchanged
Potential Difference → decreases
Energy stored → increases
Solution
Q = constant
New capacitance = KC (increases)
V′ =
(decreases)
U′ =
(decreases)
E =
⇒ E′ = 
(decreases)
New capacitance = KC (increases)
V′ =
(decreases) U′ =
(decreases) E =
⇒ E′ = (decreases)Create a free account to view solution
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