CapacitanceHard
Question
The charge on each of the capacitors 0.16 ms after the switch S is closed in figure is :
Options
A.24 μC
B.26.8 μC
C.25.2 μC
D.40 μC
Solution
q = 
q = 40(1 − e−1) μC = 40 (1 − 0.37) = 25.2μC
q = 40(1 − e−1) μC = 40 (1 − 0.37) = 25.2μC
Create a free account to view solution
View Solution FreeMore Capacitance Questions
A parallel plate capacitor C has a charge q and potential V between the plates. Work required to double the distance bet...Two parallel plate capacitors whose capacities are C and 2 C respectively, are joined in parallel. these are charged by ...Two thin dielectric slabs of dielectric constants K2 and K2 (K1 2) are inserted between plates of a parallel plate capac...A thin semi-circular ring of radius r has a positive charge q distributed uniformly over it. The net field at the centre...A circuit has a section AB as shown in the fig. With E = 10V. C1 = 1.0 μF, C2 = 2.0 μF and the potential diffe...