CapacitanceHard
Question
The charge on each of the capacitors 0.16 ms after the switch S is closed in figure is :
Options
A.24 μC
B.26.8 μC
C.25.2 μC
D.40 μC
Solution
q = 
q = 40(1 − e−1) μC = 40 (1 − 0.37) = 25.2μC
q = 40(1 − e−1) μC = 40 (1 − 0.37) = 25.2μC
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