CapacitanceMedium
Question
A parallel plate capacitor is charged and then isolated. On increasing the plate separation-
Options
A.Charge → remains constant
Potential → remains constant
Capacitance → decreases
Potential → remains constant
Capacitance → decreases
B.Charge → remains constant
Potential → increases
Capacitance → decreases
Potential → increases
Capacitance → decreases
C.Charge → remains constant
Potential → decreases
Capacitance → increases
Potential → decreases
Capacitance → increases
D.Charge → increases
Potential → increases
Capacitance → decreases
Potential → increases
Capacitance → decreases
Solution
(B) Isolated capacitor ⇒ Q = constant
separation d increase ⇒ C = decrease
Q = CV ⇒ V = increase
separation d increase ⇒ C = decrease
Q = CV ⇒ V = increase
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