ElectrostaticsHard

Question

Minimum numbers of 8μF and 250 V capacitors are used to make a conbination of16μF and 1000V are:

Options

A.4
B.32
C.8
D.3

Solution

       
Tcreate 1000 V, we need to combine 4 capacitors in series. Total capicty becomes = 2μF. In order to obtain capacity of 16μF, 8rows of this combination will beneeded in parallel.
Total capacity = 2μF × 8 = 16μF
Total number of capacitor = 4´8 = 32

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