CapacitanceMedium
Question
Minimum numbers of 8μF and 250 V capacitors are used to make a conbination of16μF and 1000V are:
Options
A.4
B.32
C.8
D.3
Solution
Tcreate 1000 V, we need to combine 4 capacitors in series. Total capicty becomes
= 2μF. In order to obtain capacity of 16μF, 8rows of this combination will beneeded in parallel.Total capacity = 2μF × 8 = 16μF
Total number of capacitor = 4´8 = 32
Create a free account to view solution
View Solution FreeMore Capacitance Questions
A slab of copper of thickness is introduced between the plates of a parallel plate capacitor where d is the seperation b...A parallel plate capacitor is charged with a battery and afterwards the battery is removed. if now with the help of insu...A parallel plate capacitor is made of two circular plates separated by a distance 5 mm and with a dielectric of dielectr...The minimum number of condensers each of capacitance of 2μF, in order to obtain resultant capacitance of 5μF w...Two same sphere having radii 10 cm & 20 cm. It has given charge 150 μC & connected by a wire. Their common potentia...