Alternating CurrentHard

Question

When 100 V DC is applied across a solenoid, a steady current of 1 A flows in it. When 100 V AC is applied across the same solenoid, the current drops to 0.5 A. If the frequency of the AC source is            150 √3/π Hz, the impedance and inductance of the solenoid are :

Options

A.200 Ω and 1/3 H
B.100 Ω and 1/16 H
C.200 Ω and 1.0 H
D.1100 Ω and 3/117 H

Solution

R = = 100Ω              x =
Z = = 200 Ω             L = H.

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